Perfect.
DICTIONARY MASTERY – DAY 2 is the heart of dict interview problems.
If you master today, 50–60% of Python coding interviews become routine.
🔥 DICTIONARY MASTERY — DAY 2
Frequency Maps, Grouping, Prefix-Hash Patterns & Core Interview Problems




🧠 DAY 2 GOAL
By the end of today, you will:
- Instantly recognize frequency-map problems
- Use dicts to collapse O(n²) → O(n)
- Solve grouping & counting problems fluently
- Explain hash-based reasoning clearly (interview-critical)
🧩 CORE DICT PATTERNS (MEMORIZE)
| Pattern | Used For |
|---|---|
| Frequency Map | Counting, uniqueness |
| Grouping | Anagrams, buckets |
| Prefix Hash | Subarray sums |
| Last Seen Index | Longest window |
| State Compression | Dynamic programming |
If you identify the pattern → solution is mechanical.
1️⃣ FREQUENCY MAP PATTERN (MOST IMPORTANT)
Used when:
- Count occurrences
- First/last unique
- Majority element
- Constraints mention “frequency”, “count”, “unique”
🔥 Q1. Character Frequency Count
s = "banana"
Optimal
from collections import defaultdict
freq = defaultdict(int)
for ch in s:
freq[ch] += 1
Why defaultdict?
- No key checks
- Cleaner
- Faster in loops
Interview line:
“I’ll use a frequency map with O(n) time.”
🔥 Q2. First Non-Repeating Character
"swiss" → 'w'
Pattern Solution
from collections import Counter
def first_unique(s):
freq = Counter(s)
for ch in s:
if freq[ch] == 1:
return ch
return None
🧠 Dict preserves insertion order → single pass
🔥 Q3. Majority Element (> n/2)
[2,2,1,2,3,2,2] → 2
Dict Approach
def majority(nums):
freq = {}
n = len(nums)
for x in nums:
freq[x] = freq.get(x, 0) + 1
if freq[x] > n // 2:
return x
Interview bonus:
- Mention Boyer–Moore as O(1) space alternative
2️⃣ GROUPING PATTERN (VERY COMMON)
Used when:
- “Group by…”
- Anagrams
- Bucketing values
🔥 Q4. Group Anagrams (CLASSIC)
["eat","tea","tan","ate","nat","bat"]
→ [["eat","tea","ate"],["tan","nat"],["bat"]]
Optimal
from collections import defaultdict
def group_anagrams(words):
groups = defaultdict(list)
for w in words:
key = tuple(sorted(w))
groups[key].append(w)
return list(groups.values())
🧠 Key insight:
- Dict key must be hashable → tuple
- Sorted string groups anagrams
Interview note:
- Time: O(n·k log k)
- Space: O(n)
🔥 Alternative (Advanced, Faster)
Use character counts as key (O(k))
Mentioning this = senior signal.
3️⃣ PREFIX HASH PATTERN (CRITICAL)
Used when:
- Subarray problems
- Running totals
- “Sum equals k”
- Negative numbers allowed
🔥 Q5. Subarray Sum Equals K
nums = [1,2,3], k=3 → 2
Optimal
from collections import defaultdict
def subarray_sum(nums, k):
seen = defaultdict(int)
seen[0] = 1
curr = 0
count = 0
for x in nums:
curr += x
count += seen[curr - k]
seen[curr] += 1
return count
🧠 Interview explanation:
- Hash cumulative sums
- Look backward in O(1)
4️⃣ LAST-SEEN INDEX PATTERN
Used when:
- Longest substring
- Window without repetition
- Distance constraints
🔥 Q6. Longest Substring Without Repeating Characters
"abcabcbb" → 3
Dict-Based Sliding Window
def longest_unique(s):
last = {}
left = 0
max_len = 0
for right, ch in enumerate(s):
if ch in last and last[ch] >= left:
left = last[ch] + 1
last[ch] = right
max_len = max(max_len, right - left + 1)
return max_len
Why dict instead of set?
- Jump window in O(1)
- No repeated shrinking
5️⃣ TWO-SUM & COMPLEMENTS (INTERVIEW STAPLE)
🔥 Q7. Two Sum
nums = [2,7,11,15], target=9 → [0,1]
Optimal
def two_sum(nums, target):
seen = {}
for i, x in enumerate(nums):
need = target - x
if need in seen:
return [seen[need], i]
seen[x] = i
🧠 Pattern:
- Store complements
- One pass
- O(n)
6️⃣ DICT AS STATE (ADVANCED THINKING)
Dicts are not just storage — they track state.
Examples:
- DP memoization
- Caching
- Visited states
- LRU cache (Day 3)
Mentioning this in interviews = strong signal.
🔥 COMMON DICT INTERVIEW TRAPS 🚨
❌ Using list instead of dict for frequency
if x in lst: # O(n)
❌ Modifying dict during iteration
for k in d:
d.pop(k) # RuntimeError
❌ Forgetting tuple conversion for keys
d[list_key] = ... # ❌
🧠 DICT INTERVIEW MENTAL MAP
When you see a problem:
- Counting? → Frequency dict
- Grouping? → Dict of lists
- Subarray? → Prefix hash
- Pair sum? → Complement map
- Longest window? → Last seen index
Say this aloud → interviewer confidence boost.
📝 DAY 2 ASSIGNMENT (MANDATORY)
1️⃣ Predict output (NO RUNNING)
from collections import defaultdict
d = defaultdict(list)
d["a"].append(1)
print(d["b"])
2️⃣ Coding (IMPORTANT)
def longest_subarray_sum_equals_k(nums, k):
"""
Works with negatives
"""
3️⃣ Explain (Interview style)
Why prefix-sum + hash map works even with negative numbers.
🔜 NEXT — DICTIONARY MASTERY DAY 3 🔥
DAY 3
- LRU cache (design + code)
- OrderedDict vs dict
- defaultdict vs Counter vs dict
- Real-world design questions
- 30+ rapid-fire dict interview drills
👉 Say “CONTINUE DICTIONARY MASTERY – DAY 3” when ready 🚀